A . tingginya
B . luas permulaan balok
C . panjang diagonal ruang
Jawab:
-
Penjelasan dengan langkah-langkah:
A. Volume balok = luas alas x tinggi V = p x l x t
1.620 cm³ = 15cm x 12cm x t
1.620 cm³ = 180cm x t
1.620 : 180 = t (materi smp, pindah ruas yang awalnya kali jadi bagi)
9 = t = tingginya
B. Luas permukaan = 2 × (pl + pt + lt).
- pl = Luas atap balok & Luas alas
- pt = Luas sisi depan & sisi belakang
- lt = Luas sisi kanan & sisi kiri
L = 2 × (p×l + p×t + l×t)
L = 2 × (15×12 + 15×9 +12×9)
L = 2 × ( 180 + 135 + 108 )
L = 2 × ( 423)
L = 864cm^2
C. [tex]Diagonal ruang = \sqrt{p^{2} +l^{2}+t^{2} }[/tex]
[tex]Diagonal ruang = \sqrt{15^{2} +12^{2}+9^{2} }[/tex]
[tex]Diagonal ruang =\sqrt{225 +144+81 }[/tex]
[tex]Diagonal ruang =\sqrt{450}[/tex]
[tex]Diagonal ruang =\sqrt{225.2}[/tex]
[tex]Diagonal ruang =\sqrt{225} dikali \sqrt{2}[/tex]
[tex]Diagonal ruang = 15 dikali \sqrt{2}[/tex]
Diagonal ruang = 15[tex]\sqrt{2}[/tex]
Note : - ( · ) = tanda kali
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